B = 40 -7 1 μ21 = 819/1650, μ31 = 382/1650, μ21 = 13842/45339,
19 -8 3
9 -3 1
while ||b2*||2 = 45339/1650 and ||b1*||2 = 1650. The proof of Theorem 5.1 breaks down for these numbers, but nevertheless, b3 = [9, -3, 1] is a (unique) shortest multiplier.
B = -1 1 0
1 2 -2
-1 0 1
Then b3 = [-1, 0, 1] and b3 - b1 = [0, -1, 1] are the shortest multipliers.
B = 3 -4 1 μ21 = -7/26, μ31 = 1/2,
-10 -3 11 μ32 = -2899/5931.
6 0 -5
Then b3 = [6, 0, -5], b3 - b1 = [3, 4, -6] and b3 + b2 = [-4, -3, 6] are the shortest multipliers.Last modified 22nd January 2002