B = 40 -7 1 μ21=819/1650, μ31=382/1650, μ21=13842/45339,
19 -8 3
9 -3 1
while ||b2*||2=45339/1650 and ||b1*||2=1650. The proof of Theorem 5.1 breaks down for these numbers, but nevertheless, b3=[9, -3, 1] is a (unique) shortest multiplier.
B = -1 1 0
1 2 -2
-1 0 1
Then b3=[-1, 0, 1] and b3-b1=[0, -1, 1] are the shortest multipliers.
B= 3 -4 1 μ21=-7/26, μ31=1/2,
-10 -3 11 μ32=-2899/5931.
6 0 -5
Then b3=[6, 0, -5], b3-b1=[3, 4, -6] and b3+b2=[-4, -3, 6] are the shortest multipliers.Last modified 22nd January 2002